Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
Each number in C may only be used once in the combination.
Note:
- All numbers (including target) will be positive integers.
- Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
- The solution set must not contain duplicate combinations.
For example, given candidate set
A solution set is:
10,1,2,7,6,1,5
and target 8
, A solution set is:
[1, 7]
[1, 2, 5]
[2, 6]
[1, 1, 6]
Solution
class Solution: # @param candidates, a list of integers # @param target, integer # @return a list of lists of integers def combinationSum2(self, candidates, target): candidates.sort() solution =[] self.combinationSum2Rec(candidates, target, 0, 0, [], solution) return solution def combinationSum2Rec(self, candidates, target, index, sum, tempList, solution): if sum == target: solution.append(list(tempList)) return for i in range(index, len(candidates)): if (i==index or candidates[i-1]!=candidates[i]) and sum+candidates[i]<=target: tempList.append(candidates[i]) self.combinationSum2Rec(candidates, target, i+1, sum+candidates[i], tempList, solution) tempList.pop()
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