Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
Each number in C may only be used once in the combination.
Note:
- All numbers (including target) will be positive integers.
- Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
- The solution set must not contain duplicate combinations.
For example, given candidate set
A solution set is:
10,1,2,7,6,1,5 and target 8, A solution set is:
[1, 7] [1, 2, 5] [2, 6] [1, 1, 6] Solution
class Solution:
# @param candidates, a list of integers
# @param target, integer
# @return a list of lists of integers
def combinationSum2(self, candidates, target):
candidates.sort()
solution =[]
self.combinationSum2Rec(candidates, target, 0, 0, [], solution)
return solution
def combinationSum2Rec(self, candidates, target, index, sum, tempList, solution):
if sum == target:
solution.append(list(tempList))
return
for i in range(index, len(candidates)):
if (i==index or candidates[i-1]!=candidates[i]) and sum+candidates[i]<=target:
tempList.append(candidates[i])
self.combinationSum2Rec(candidates, target, i+1, sum+candidates[i], tempList, solution)
tempList.pop()
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