Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
Solution:
/**
* Definition for binary tree
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public TreeNode sortedArrayToBST(int[] num) {
return sortedArrayToBST(num, 0, num.length-1);
}
public TreeNode sortedArrayToBST(int[] num, int begin, int end) {
if (begin>end)
return null;
int midPoint= (begin+end)/2;
TreeNode solution = new TreeNode(num[midPoint]);
solution.left = sortedArrayToBST(num, begin, midPoint-1);
solution.right = sortedArrayToBST(num, midPoint+1, end);
return solution;
}
}
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