Given a collection of intervals, merge all overlapping intervals.
For example,
Given
return
Given
[1,3],[2,6],[8,10],[15,18],return
[1,6],[8,10],[15,18].Solution:
/**
* Definition for an interval.
* public class Interval {
* int start;
* int end;
* Interval() { start = 0; end = 0; }
* Interval(int s, int e) { start = s; end = e; }
* }
*/
public class Solution {
public List<Interval> merge(List<Interval> intervals) {
Collections.sort(intervals, new Comparator<Interval>() {
public int compare(Interval i1, Interval i2) {
return i1.start - i2.start;
}
});
int i=1;
while(i<intervals.size())
{
if (intervals.get(i-1).end >= intervals.get(i).start)
{
intervals.get(i-1).end = Math.max(intervals.get(i-1).end, intervals.get(i).end);
intervals.remove(i);
}
else
i++;
}
return intervals;
}
}
No comments :
Post a Comment